The decomposition of Homk(S, k) into indecomposable injectives

Amnon Neeman*

*Corresponding author for this work

    Research output: Contribution to journalArticlepeer-review

    1 Citation (Scopus)

    Abstract

    Let S be an algebra essentially of finite type over a field k. Then, Homk(S, k) is an injective S–module, and the Matlis structure theorem (Matlis, E.: Pacific J. Math. 8, 511–528 1958) tells us that it can be written as a direct sum of indecomposable injectives. We compute the multiplicities of these injectives. Let p be a prime ideal in S, and let I (p) be the injective hull of S/p. If the residue field k(p) is algebraic over k, then the multiplicity of I (p) is μ(p) = 1. If the transcendence degree of k(p) over k is ≥ 1, then μ(p) ≥ |#k|ℵ0, that is the multiplicity is no less than the cardinality of the field k raised to the power ℵ0. If S is finitely generated over k, then equality holds, that is, μ(p) = |#k|ℵ0. For k(p) of transcendence degree ≤ 1, the result is not surprising, but for k(p) of transcendence degree ≥ 2 it is not clear that μ(p) _= 0. We prove the result by induction on the transcendence degree, and the key is that we produce an injective map, from a space whose dimension we know by induction and into the space whose dimension we want to estimate. The interest in the result comes from the fact that the size of μ(p) measures the failure of a natural map ψ(f): f× −→ f! to be an isomorphism. Here, f× and f! are the twisted inverse image functors of Grothendieck duality.

    Original languageEnglish
    Pages (from-to)331-338
    Number of pages8
    JournalActa Mathematica Vietnamica
    Volume40
    Issue number2
    DOIs
    Publication statusPublished - 1 Jun 2015

    Fingerprint

    Dive into the research topics of 'The decomposition of Homk(S, k) into indecomposable injectives'. Together they form a unique fingerprint.

    Cite this